[nycphp-talk] mysql_insert_id Strangeness
Brian Pang
bpang at bpang.com
Tue Aug 5 12:26:33 EDT 2003
ok, the C code is good for comparison and isolating where the problem
might be, or at least not with PHP...
good luck
>
> > using the mysql client, are you able to replicate the problem? meaning,
> > do you get the right mysql_insert_id when performing inserts in the
> > mysql client
>
> An illustrative C program (below) shows the same behavior, so it
doesn't seem to be anything with PHP.
>
> And even the MySQL documentation says something different than the
behavior, from: http://www.mysql.com/doc/en/mysql_insert_id.html
>
> "Note that mysql_insert_id() returns 0 if the previous query does not
generate an AUTO_INCREMENT value..."
>
> As Carlos pointed out, this is a gross documentation ambiguity. The
statement above is false according to the actual behavior, since an
INSERT that fails because of a UNIQUE index doesn't generate an
AUTO_INCREMENT value, yet mysql_insert_id() doesn't return 0. This
seems like a new quirk, although I could be wrong.
>
> I'm going to bounce this off the mysql guys and see what they say.
>
> H
>
>
>
>
>
> #include <stdio.h>
> #include <stdlib.h>
> #include <string.h>
> #include <unistd.h>
> #include "mysql/mysql.h"
>
> MYSQL mysql;
> MYSQL_RES *mysql_result;
> MYSQL_ROW mysql_row;
>
> char *links[6] = {"http://hans.zaunere.com",
> "http://zaunere.com",
> "http://hans.zaunere.com",
> "http://nyphp.org",
> "http://lists.nyphp.org",
> "http://nyphp.org"};
>
>
> int main(void) {
>
> int i,R_linkid;
> char insert_string[255];
>
> mysql_init(&mysql);
>
> mysql_real_connect(&mysql,"localhost","ptips","ptips--",NULL,0,NULL,0);
>
> for( i = 0; i < 6; ++i ) {
> printf("\nLink %d: %s\n", i,links[i]);
> sprintf(insert_string, "INSERT INTO ptips.links (linkid,link)
> VALUES(NULL,'%s')",links[i]);
>
> mysql_real_query(&mysql,insert_string,sizeof(insert_string));
>
> R_linkid = mysql_insert_id(&mysql);
>
> printf("\nR_linkid: %d\n",R_linkid);
> }
>
> }
>
>
>
>
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